Solid State

On this page
  1. Direct answer
  2. What you must remember
  3. Common confusion
  4. Exam-focused takeaway
  5. Frequently asked questions
  6. Related topics

Direct answer

Solid state chemistry describes crystals through the unit cell, the smallest repeating box of the lattice. The three cubic cells carry Z = 1 (simple), 2 (body-centred) and 4 (face-centred) atoms with packing efficiencies 52.4, 68 and 74 per cent; density follows d = Z × M / (a^3 × N_A). Ionic structures are read as close-packed anions with cations in octahedral or tetrahedral voids, and point defects explain colour, conductivity and semiconducting behaviour.

What you must remember

  • Atoms per cell: simple cubic 1 (eight corners × 1/8), bcc 2 (plus one body-centre atom), fcc 4 (plus six faces × 1/2); coordination numbers 6, 8 and 12.
  • Packing efficiency: 52.4 per cent (sc), 68 per cent (bcc), 74 per cent (fcc and hcp) — only fcc and hcp are close-packed.
  • Edge relations: sc a = 2r; bcc a = 4r/√3 (body diagonal 4r); fcc a = 2√2 r (face diagonal 4r).
  • Density: d = Z × M / (a^3 × N_A), edge in cm for d in g cm^-3 — the standard numerical here.
  • Voids: N close-packed spheres give N octahedral and 2N tetrahedral voids; radius ratios 0.414 (octahedral) and 0.225 (tetrahedral) place a cation.
  • Structures: NaCl 6:6 (Cl- fcc, Na+ in octahedral voids), CsCl 8:8, ZnS zinc blende 4:4, CaF2 8:4, Na2O antifluorite.
  • Schottky defect — paired cation-anion vacancies, density falls (NaCl, CsCl); Frenkel — an ion (small cation) shifts to an interstitial site, density unchanged (ZnS, AgCl); interstitial defects raise density.
  • F-centres, electrons trapped in anion vacancies, colour alkali halides: excess Li pink, Na yellow, K violet.
  • Doping: group 15 (As in Si) gives n-type electrons; group 13 (B, Al, In) gives p-type holes. Magnetic classes: ferromagnetic Fe, antiferromagnetic MnO, ferrimagnetic Fe3O4.

Common confusion

The classic muddle is Schottky versus Frenkel: Schottky is paired vacancy with density loss, Frenkel is dislocation with density unchanged — Frenkel needs an ion small enough for the interstitial site. Students swap the radius-ratio thresholds, count fcc atoms as 14, and mix up n and p doping — remember the rule: group 15 donor gives n-type, group 13 acceptor gives p-type.

Exam-focused takeaway

JEE Main tests the computational core: atoms per cell, density from the edge, packing fractions, void counting, one-line defect identification. JEE Advanced (where this chapter has traditionally carried weight) pushes reasoning — formula units from occupied voids, radius-ratio structure prediction, F-centre colour questions and doping with band ideas. Draw the cell and mark shared contributions before counting; every numerical begins as geometry bookkeeping.

Frequently asked questions

How many atoms belong to one fcc unit cell?

Four: eight corners × 1/8 gives one, six faces × 1/2 gives three.

What is the packing efficiency of bcc?

68 per cent, below fcc's 74 per cent, because the body-centre atom leaves gaps along the cell edges.

How do Schottky and Frenkel defects differ?

Schottky removes a cation-anion pair (density decreases); Frenkel shifts a small ion into an interstitial site (density unchanged, vacancy plus interstitial created).

What is an F-centre?

An electron trapped in an anion vacancy; it absorbs visible light, colouring crystals like NaCl heated in sodium vapour.

Why is NaCl 6:6 coordinated?

Chloride forms an fcc lattice and Na+ fits the octahedral voids by radius ratio; each ion touches six of the other kind.

What distinguishes n-type from p-type silicon?

n-type is doped with a group 15 donor supplying electrons; p-type with a group 13 acceptor creating holes.

Same topic for other exams

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