Polar Line and Pole of a Conic

On this page
  1. Direct answer
  2. What you must remember
  3. Finding and using one polar
  4. How the exam frames it
  5. Frequently asked questions
  6. Related topics

Direct answer

The polar of a point P(x1, y1) with respect to a conic is the straight line T = 0 built by halving the mixed terms: for the circle x^2 + y^2 = a^2 it is xx1 + yy1 = a^2; for the general circle x^2 + y^2 + 2gx + 2fy + c = 0 it is xx1 + yy1 + g(x + x1) + f(y + y1) + c = 0; for the parabola y^2 = 4ax it is yy1 = 2a(x + x1); for the ellipse x^2/a^2 + y^2/b^2 = 1 it is xx1/a^2 + yy1/b^2 = 1. When P lies on the conic, its polar is the tangent at P; when P lies outside, the polar is the chord of contact of the two tangents from P. The relationship is reciprocal — La Hire's theorem: P lies on the polar of Q exactly when Q lies on the polar of P — and for the parabola the polar of the focus is the directrix itself.

What you must remember

  • Circle polar: xx1 + yy1 = a^2 for x^2 + y^2 = a^2; with general equation use the T-form with g(x + x1) + f(y + y1) + c.
  • Parabola polar: yy1 = 2a(x + x1) for y^2 = 4ax; hyperbola and ellipse follow the same xx1/a^2 ± yy1/b^2 = 1 pattern.
  • Tangent as special case: P on the conic makes T = 0 the tangent at P — the same formula serves tangents and polars, which is why memorising one T = 0 covers both chapters.
  • Chord of contact: P outside the conic gives two real tangents touching at Q and R; the polar is the line QR.
  • La Hire's theorem: P on the polar of Q ⟺ Q on the polar of P — the pole-polar relation is symmetric.
  • Conjugate points and lines: two points are conjugate when each lies on the other's polar; two lines are conjugate when each passes through the other's pole; the centre of a central conic has the line at infinity as its polar.
  • Focus-directrix cameo: for the parabola y^2 = 4ax, the polar of the focus (a, 0) is y·0 = 2a(x + a), i.e., x = -a, the directrix; for central conics, the polar of a focus is the corresponding directrix.

Finding and using one polar

Take the circle x^2 + y^2 = 9 and the exterior point P(4, 5). Its polar is 4x + 5y = 9. Where does this line sit? Its distance from the centre is 9/√(16 + 25) = 9/√41 ≈ 1.4, well inside the radius 3, so the polar cuts the circle in two real points — and those points are exactly the contact points of the two tangents drawn from P (the chord of contact). The geometry is self-checking: an exterior point has its polar pass inside, and an interior point has its polar fall wholly outside (distance a^2/d exceeds the radius when d < a). Now exercise La Hire: pick Q(0, 9/5), which satisfies 4 × 0 + 5 × (9/5) = 9, so Q lies on the polar of P. The polar of Q is 0·x + (9/5)y = 9, that is, y = 5 — and P(4, 5) lies on it, as reciprocity demands. Two computations, one theorem confirmed, and the pattern generalises verbatim to ellipse and parabola with their T = 0 forms.

How the exam frames it

JEE Main asks for the polar (chord of contact) of a given point with respect to a given circle or parabola — essentially the T = 0 formula evaluated — and for the pole of a given line by solving the coefficient matching. Advanced deploys La Hire and conjugacy: find the locus of points whose polars pass through a fixed point (answer: the polar of that point — a locus question answered by one line), or prove concyclicity of contact points. The predictable slips: using T = 0 with the point coordinates swapped into the wrong slots (the pattern is xx1 and yy1 — cross terms do not exist in these forms); treating the polar of an interior point as a chord of contact (no real tangents exist from inside, so the polar misses the conic); and confusing the polar with the normal or the diameter through the point. A favourite property-based multiple choice: the polars of all points on a straight line are concurrent — at the pole of that line — which is La Hire read backwards. Conic sections and tangents sit in both syllabi, with pole-polar among the classic Advanced extensions.

Frequently asked questions

What is the polar of a point with respect to x^2 + y^2 = a^2?

The line xx1 + yy1 = a^2; for the general circle, xx1 + yy1 + g(x + x1) + f(y + y1) + c = 0.

When does the polar become the chord of contact?

When the point lies outside the conic: the two real tangents from it touch at two points, and the polar is the line joining them.

What does La Hire's theorem say?

Point P lies on the polar of Q if and only if Q lies on the polar of P — the pole-polar relation is perfectly symmetric.

What is the polar of a point lying on the conic itself?

The tangent at that point — the single formula T = 0 degenerates from chord of contact to tangent.

What is the polar of the focus of y^2 = 4ax?

The directrix x = -a; more generally each focus of a conic has the corresponding directrix as its polar.

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