Volume of Solids of Revolution

On this page
  1. Direct answer
  2. What you must remember
  3. Generating a sphere and a torus
  4. How the exam frames it
  5. Frequently asked questions
  6. Related topics

Direct answer

Rotating a plane region about a line sweeps a solid whose volume calculus computes by slicing. About the x-axis, the disc method gives V = π ∫ y^2 dx, each slice being a disc of radius y. If the region has a hole (rotation about an axis with the region offset), the washer method subtracts: V = π ∫ (R^2 - r^2) dx with R and r the outer and inner radii. About the y-axis, the shell method wraps cylinders: V = 2π ∫ x y dx, each shell contributing circumference 2πx times height y times thickness dx. Off-axis rotation replaces the radius by the distance from the curve to the axis: revolving y = f(x) about y = c uses π ∫ (f(x) - c)^2 dx. Pappus's theorem compresses special cases to arithmetic: V = (area) × (2π × distance travelled by the centroid), giving the torus volume 2π^2 R r^2 instantly.

What you must remember

  • Disc method: about the x-axis, V = π ∫[a to b] y^2 dx; about the y-axis for x = g(y), V = π ∫ x^2 dy.
  • Washer method: V = π ∫ (R^2 - r^2) dx when the swept region has a hole — outer radius minus inner radius, both squared first.
  • Shell method: about the y-axis, V = 2π ∫ x y dx; ideal when solving for x is ugly or the height is naturally a function of x.
  • Off-axis rotation: about the line y = c, radius = |f(x) - c|, so V = π ∫ (f(x) - c)^2 dx; about x = c for shells, V = 2π ∫ |x - c| y dx.
  • Sphere check: y = √(a^2 - x^2) revolved about the x-axis gives π ∫[-a to a] (a^2 - x^2) dx = 4πa^3/3 — the built-in sanity test for any method.
  • Pappus (Guldinus) theorem: V = A × 2π d̄, where d̄ is the centroid's distance from the axis; the torus from a circle of radius r centred (R, 0) has V = πr^2 × 2πR = 2π^2 R r^2.
  • Limits follow the variable of integration: dx for x-axis discs and y-axis shells, dy for y-axis discs — a mismatch of limits and variable is the commonest computational wreck.

Generating a sphere and a torus

The sphere first, because it calibrates everything: rotate y = √(a^2 - x^2) about the x-axis. V = π ∫[-a to a] (a^2 - x^2) dx = π [a^2 x - x^3/3] from -a to a = π [(a^3 - a^3/3) - (-a^3 + a^3/3)] = π (4a^3/3) = 4πa^3/3, the textbook value confirming the machinery. Now the torus by two routes. By washers about the y-axis, the circle (x - R)^2 + y^2 = r^2 (R > r) gives outer radius R + √(r^2 - (x - R)^2) and inner radius R - √(r^2 - (x - R)^2); squaring and subtracting leaves 4R√(r^2 - (x - R)^2), so V = π ∫ 4R√(r^2 - (x - R)^2) dx over [R - r, R + r], which is 4πR times a half-circle area πr^2/2 — that is, 2π^2 R r^2 after the standard substitution. By Pappus the same answer is one line: area πr^2, centroid at the circle's centre travelling 2πR, so V = 2π^2 R r^2. The two routes' agreement is the theorem's proof in miniature and the reason examiners accept the shortcut when the centroid is known.

How the exam frames it

JEE Main tests the disc and shell formulae on elementary regions — y = x^2 about the x-axis (πa^5/5 over [0, a]), y = sin x, a rectangle about one side — mostly as numerical-value questions. Advanced prefers off-axis rotation (y = x^2 about y = 4, or the region between two curves about the y-axis), the washer construction with genuinely two curves, and Pappus applied to triangles and semicircles whose centroids are known from coordinate geometry. The trademark slips: using the shell formula with y^2 instead of y (mixing the two templates); revolving about y = c but leaving the radius as f(x) rather than f(x) - c; forgetting that washers subtract squared radii, not radii themselves — π(R - r)^2 is the single most marked error in this chapter. Also note the dimensional check habit: a volume answer must carry length cubed, which instantly exposes a forgotten π or a wrong power. Solids of revolution belong to the application-of-integrals unit in both syllabi.

Frequently asked questions

What is the disc method formula for volume of revolution?

About the x-axis, V = π ∫ y^2 dx, each slice of thickness dx being a disc of radius y and volume πy^2 dx.

When is the washer method needed instead of the disc method?

When the region does not touch the axis, leaving a hole: V = π ∫ (R^2 - r^2) dx with outer radius R and inner radius r.

How does the shell method compute volumes about the y-axis?

By cylindrical shells, V = 2π ∫ x y dx — circumference 2πx times height y times thickness dx — best when y is easier to express as a function of x.

How does rotation about a line y = c change the formula?

The radius becomes the distance |f(x) - c|, so V = π ∫ (f(x) - c)^2 dx; failing to shift the radius is the chapter's most frequent error.

What does Pappus's theorem say about volumes of revolution?

V equals the generating area times the distance its centroid travels: V = 2π d̄ A, giving the torus 2π^2 R r^2 without any integration.

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